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  1. #1
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    number

    Can someone pls guide me through . Thanks

    Q : The binary operation , * , on rational numbers is as follows . For x and y are both rational numbers .

    x*y = x+y-xy .

    (a) Prove that * is associative
    (b) Determine if * is distributive with respect to addition .
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  2. #2
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    Hello, mathaddict!

    The binary operation * on rational numbers is as follows.

    For rationals x\text{ and }y\!:\;\;x*y \:=\: x+y-xy

    (a) Prove that * is associative
    We want to show that: . (a*b)*c \:=\:a*(b*c)


    (a*b)*c \;=\;(a+b-ab)*c

    . . . . . . =\;(a + b-ab) + c - (a+b-ab)c

    . . . . . . =\; a + b - ab + c - ac - bc + abc

    . . . . . . = \;a + b + c -(ab + bc + ac) + abc .[1]


    a*(b*c) \;=\;a*(b + c - bc)

    . . . . . . = \;a + (b + c - bc) - a(b + c - bc)

    . . . . . . =\;a + b + c + -bc - ab - ac + abc

    . . . . . . = \;a + b + c - (ab + bc + ac) + abc .[2]


    Since [1] = [2], the operation is associative.





    (b) Determine if * is distributive with respect to addition .
    Does a*(b+c) \:=\:(a*b) + (a*c) ?


    a*(b+c) \;=\;a + (b+c) - a(b+c)

    . . . . . . . = \;a + b + c - ab - ac .[3]


    (a*b) + (a*c) \;=\;(a + b - ab) + (a + c - ac)

    . . . . . . . = \;{\color{red}2}a + b + c - ab - ac .[4]


    Since [3] \neq [4], the operation is not distributive over addition.

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