Blue represents the base of the log.

$\displaystyle log (2a) (4a^2)^3 = x$Problem:

I converted the logarithm into exponential form.Attempted Solution:

$\displaystyle 2a^x = (4a^2)^3$

$\displaystyle 2a^x = 64a^6$

$\displaystyle 2a^x/2 = 64a^6/2$

$\displaystyle a^x = 32a^6$

I cannot see where to go from here.

Could someone please help?