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Math Help - solve 4^(2x+1).5^x-2=6^1-x

  1. #1
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    solve 4^(2x+1).5^x-2=6^1-x

    need help with this too lol
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by 24680 View Post
    need help with this too lol
    Do you mean:

    4^(2x+1) (.5^x) - 2=6^(1-x)

    RonL
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  3. #3
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    Quote Originally Posted by 24680 View Post
    need help with this too lol
    Hello,

    I assume that your problem reads:

    4^(2x+1) * 5^(x-2) = 6^(1-x)

    Expand the powers:

    4*(4^2)^x * 5^x / 25 = 6 / (6^x)

    Rearrange so that all constant numbers are at the RHS of the equation:

    16^x * 5^x * 6^x = (6 * 25)/4

    (480)^x = 150/4

    x is the logarithm of 150/4 to the base of 480:

    x = [log(150/4)] / (log(480)] ≈ 0.587053207...

    tschüss

    EB
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