need help with this too lol

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- Oct 8th 2006, 11:57 AM24680solve 4^(2x+1).5^x-2=6^1-x
need help with this too lol

- Oct 8th 2006, 12:09 PMCaptainBlack
- Oct 8th 2006, 12:13 PMearboth
Hello,

I assume that your problem reads:

4^(2x+1) * 5^(x-2) = 6^(1-x)

Expand the powers:

4*(4^2)^x * 5^x / 25 = 6 / (6^x)

Rearrange so that all constant numbers are at the RHS of the equation:

16^x * 5^x * 6^x = (6 * 25)/4

(480)^x = 150/4

x is the logarithm of 150/4 to the base of 480:

x = [log(150/4)] / (log(480)] ≈ 0.587053207...

tschüss

EB