I'm quite confused by the function y = |x^2 - 1|
I understand that y = x^2 - 1 when x^2 - 1 > 0 etc
But how do you solve it?
You get x^2 - 1 > 0
x^2 > 1
x > + or - 1
but it should be x<-1 and x>1
Is there some sort of inequation sign change when one of the sides is square rooted? Thanks in advance