Originally Posted by

**BritneyPO** I'm really desperate!

Graph this parabola

x=y^2 and y=-(x-2)^2

Write logbase2 64=6 as an exponential equation.

Set up a table of values for x and solve for y. Here are a few. Plot the points

Code:

x | y
-----
0 | 0
4 | +/-2
9 | +/-3
16| +/-4

The domain is all positive real numbers and zero. The parabola opens to the right with its vertex at (0, 0) and the x-axis is its axis of symmetry.

Do the same thing here. Set up your table and plot some points

Code:

x | y
------
0 | -4
1 | -1
-1 | -9
2 | 0
-2 |-16
3 | -1
-3 |-25

This parabola opens downward because a<0. The vertex is at (2, 0) and the y-intercept is -4

is the same as