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4t(t+5) ______ 24t^2(t-5)

Quote: Originally Posted by Panama 4t(t+5) ______ 24t^2(t-5) $\displaystyle =\frac{ {4t}(t+5)}{24t^2(t-5)}$ $\displaystyle =\frac{\bold{\rlap{\color{red}=}}4t (t+5)}{\bold{\rlap{\color{red}==}}24t \cdot t(t-5)}$ $\displaystyle =\frac{t+5}{6t(t-5)}$ $\displaystyle =\frac{t+5}{6t^2-30t}$

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