To get rid of the 1/2 how is it done? 2d+4c=1/2 4b+2a is it 2/1(2d+4c)=2/1(1/2 4b+2a) so 4d+8c=4b+2a or 2/1(2d+4c)= (2/1)1/2 4b+2a so 4d+8c=4b+2a or something different? Thanks for any help you have.
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Originally Posted by brentwoodbc To get rid of the 1/2 how is it done? 2d+4c=1/2 4b+2a is it 2/1(2d+4c)=2/1(1/2 4b+2a) so 4d+8c=4b+2a or 2/1(2d+4c)= (2/1)1/2 4b+2a so 4d+8c=4b+2a or something different? Thanks for any help you have. Hello bentwoodbc, I guess I'm unsure what you mean. Is this the problem if so you can use the distributive law to simplify if it is just Good luck.
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