To get rid of the 1/2 how is it done?
2d+4c=1/2 4b+2a
is it
2/1(2d+4c)=2/1(1/2 4b+2a)
so
4d+8c=4b+2a
or
2/1(2d+4c)= (2/1)1/2 4b+2a
so
4d+8c=4b+2a
or something different?
Thanks for any help you have.
Hello bentwoodbc,
I guess I'm unsure what you mean. Is this the problem
$\displaystyle 2d+4c=\frac{1}{2}(4b+2a)$
if so you can use the distributive law to simplify
$\displaystyle 2d+4c=\frac{1}{2}\cdot 4b+\cdot \frac{1}{2} 2a$
$\displaystyle 2d+4c=2b+a$
if it is just $\displaystyle \frac{1}{2}4b=2b$
Good luck.