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Math Help - multiply by reciprocal

  1. #1
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    Question multiply by reciprocal

    To get rid of the 1/2 how is it done?

    2d+4c=1/2 4b+2a

    is it

    2/1(2d+4c)=2/1(1/2 4b+2a)
    so
    4d+8c=4b+2a

    or

    2/1(2d+4c)= (2/1)1/2 4b+2a
    so
    4d+8c=4b+2a

    or something different?

    Thanks for any help you have.
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by brentwoodbc View Post
    To get rid of the 1/2 how is it done?

    2d+4c=1/2 4b+2a

    is it

    2/1(2d+4c)=2/1(1/2 4b+2a)
    so
    4d+8c=4b+2a

    or

    2/1(2d+4c)= (2/1)1/2 4b+2a
    so
    4d+8c=4b+2a

    or something different?

    Thanks for any help you have.
    Hello bentwoodbc,

    I guess I'm unsure what you mean. Is this the problem

    2d+4c=\frac{1}{2}(4b+2a)

    if so you can use the distributive law to simplify

    2d+4c=\frac{1}{2}\cdot 4b+\cdot \frac{1}{2} 2a

    2d+4c=2b+a

    if it is just \frac{1}{2}4b=2b

    Good luck.
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