Use the quadratic formula to solve: -4x^2 + 13x - 3 = 0
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# infront of x^2 is a infront on x is b infront of nothing constant term is c also make sure equation is in standard form which it is. then fill into x= -b sqrt (b^2 -4ac) 2a
Originally Posted by brentwoodbc # infront of x^2 is a infront on x is b infront of nothing constant term is c also make sure equation is in standard form which it is. then fill into x= -b sqrt (b^2 -4ac) 2a Yes, I tried that but I didn't get the right answer.
make sure you keep track of negatives "2 neg. = pos." also what is the given answer?
also its + the sqrt sorry so -b plus or minus the sqrt
I get x=1/4,3
I got 2 ± √6 instead of 7 ± 5√2. EDIT: Sorry, I meant I got -13 ± √217/ -8 instead of 9 ± √89/ 2.
Last edited by Joker37; November 28th 2008 at 09:45 AM.
Originally Posted by Joker37 I got 2 ± √6 instead of 7 ± 5√2. thats odd maybe someone else can chime in on this but I get -13 +/- √121 -8 and 121 is a perfect square so -13 +/- 11 -8 so 1/4 , 3
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