Use the quadratic formula to solve:

-4x^2 + 13x - 3 = 0

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- Nov 28th 2008, 10:06 AMJoker37The quadratic formula
Use the quadratic formula to solve:

-4x^2 + 13x - 3 = 0 - Nov 28th 2008, 10:09 AMbrentwoodbc
# infront of x^2 is a

infront on x is b

infront of nothing constant term is c

also make sure equation is in standard form which it is.

then fill into

x=__-b sqrt (b^2 -4ac)__

2a - Nov 28th 2008, 10:13 AMJoker37
- Nov 28th 2008, 10:14 AMbrentwoodbc
make sure you keep track of negatives "2 neg. = pos."

also what is the given answer? - Nov 28th 2008, 10:17 AMbrentwoodbc
also its

__+__the sqrt sorry so -b plus or minus the sqrt - Nov 28th 2008, 10:20 AMbrentwoodbc
I get x=1/4,3

- Nov 28th 2008, 10:23 AMJoker37
I got 2 ± √6 instead of 7 ± 5√2.

EDIT: Sorry, I meant I got -13 ± √217/ -8 instead of 9 ± √89/ 2. - Nov 28th 2008, 10:28 AMbrentwoodbc