# Math Help - equations

1. ## equations

find the values of x such that f(x)=0, if f(x)=x^3 - 6x^2 + 11x - 6

my ans:

i got f(x)=0 by substituting x=1
how to solve from there?

2. Originally Posted by Faz
find the values of x such that f(x)=0, if f(x)=x^3 - 6x^2 + 11x - 6

my ans:

i got f(x)=0 by substituting x=1
how to solve from there?
We know then that $x-1|x^3-6x^2+11x-6$

So simplify $\frac{x^3-6x^2+11x-6}{x-1}=???$ to get a simple quadratic solvable by any number of ways.

3. ## equations

i divided and got

(x-1) (x-3) (x-2)

ans : 1,3,2