Thread: equations

find the values of x such that f(x)=0, if f(x)=x^3 - 6x^2 + 11x - 6

my ans:

i got f(x)=0 by substituting x=1
how to solve from there?

Originally Posted by Faz

find the values of x such that f(x)=0, if f(x)=x^3 - 6x^2 + 11x - 6

my ans:

i got f(x)=0 by substituting x=1
how to solve from there?

We know then that

So simplify to get a simple quadratic solvable by any number of ways.

i divided and got

(x-1) (x-3) (x-2)

ans : 1,3,2