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  1. #1
    Faz
    Faz is offline
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    equations

    find the values of x such that f(x)=0, if f(x)=x^3 - 6x^2 + 11x - 6

    my ans:

    i got f(x)=0 by substituting x=1
    how to solve from there?
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by Faz View Post
    find the values of x such that f(x)=0, if f(x)=x^3 - 6x^2 + 11x - 6

    my ans:

    i got f(x)=0 by substituting x=1
    how to solve from there?
    We know then that x-1|x^3-6x^2+11x-6

    So simplify \frac{x^3-6x^2+11x-6}{x-1}=??? to get a simple quadratic solvable by any number of ways.
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  3. #3
    Faz
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    equations

    i divided and got

    (x-1) (x-3) (x-2)

    ans : 1,3,2
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