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Math Help - SAT algebra problem

  1. #1
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    SAT algebra problem

    here is the problem:

    There are 75 more women than men enrolled at Linden College. If there are 'n' men enrolled then in terms of 'n' what percentage of those enrolled are men?

    Answer choices:

    A) n/ (n+75) %

    B) n/ (2n+75) %

    C) n/ (100(2n+75)) %

    D) 100n/ (n+75) %

    E) 100n/ (2n+75) %


    Thanks for the help guys... a good explanation should help me out
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  2. #2
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    [quote=Gman8990;227004]here is the problem:

    There are 75 more women than men enrolled at Linden College. If there are 'n' men enrolled then in terms of 'n' what percentage of those enrolled are men?

    Answer choices:

    A) n/ (n+75) %

    B) n/ (2n+75) %

    C) n/ (100(2n+75)) %

    D) 100n/ (n+75) %


    Hey mate,

    The Percentage of Men enrolled is calculated using

    %Men = (Number of Men)/(Total Number of Men and Women)

    we know Number of Men = n
    and that there are 75 more females than Men
    Therefore,

    Number of Women = n + 75

    Thus,
    Total number of People = (n) + (n + 75) = 2n + 75

    Thus

    Percentage Men = n/(2n+5)

    hence (b)

    Hope this helps,

    Regards,

    David
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  3. #3
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    Technically, I think David is right, but the way the answers are set out with a % sign at the end suggests that you need to multiply by 100. The fraction of those enrolled that are men is indeed n/(2n+75) but to convert to a percentage you need to multiply by 100
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  4. #4
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    Quote Originally Posted by badgerigar View Post
    Technically, I think David is right, but the way the answers are set out with a % sign at the end suggests that you need to multiply by 100. The fraction of those enrolled that are men is indeed n/(2n+75) but to convert to a percentage you need to multiply by 100
    hello everyone,
    The % sign is a mere formality, yes it is certainly true that multiplication by 100 will produce the manufactured representation of percentage, however the decimal version is certainly adequate, and as long as the user is specific as to what format they have chosen then no inaccuracies exist.

    I mean this with no offense to any contributions that all other members may have made,

    Regards,

    David
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