1. ## SAT algebra problem

here is the problem:

There are 75 more women than men enrolled at Linden College. If there are 'n' men enrolled then in terms of 'n' what percentage of those enrolled are men?

A) n/ (n+75) %

B) n/ (2n+75) %

C) n/ (100(2n+75)) %

D) 100n/ (n+75) %

E) 100n/ (2n+75) %

Thanks for the help guys... a good explanation should help me out

2. [quote=Gman8990;227004]here is the problem:

There are 75 more women than men enrolled at Linden College. If there are 'n' men enrolled then in terms of 'n' what percentage of those enrolled are men?

A) n/ (n+75) %

B) n/ (2n+75) %

C) n/ (100(2n+75)) %

D) 100n/ (n+75) %

Hey mate,

The Percentage of Men enrolled is calculated using

%Men = (Number of Men)/(Total Number of Men and Women)

we know Number of Men = n
and that there are 75 more females than Men
Therefore,

Number of Women = n + 75

Thus,
Total number of People = (n) + (n + 75) = 2n + 75

Thus

Percentage Men = n/(2n+5)

hence (b)

Hope this helps,

Regards,

David

3. Technically, I think David is right, but the way the answers are set out with a % sign at the end suggests that you need to multiply by 100. The fraction of those enrolled that are men is indeed n/(2n+75) but to convert to a percentage you need to multiply by 100