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Math Help - Please help to simplify..

  1. #1
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    Please help to simplify..

    Simplify:

    -4(x^2)^7(w^8)^3
    22x^6(w^10)^3 z
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by Elli View Post
    Simplify:

    -4(x^2)^7(w^8)^3
    22x^6(w^10)^3 z
    This is the same as saying -\frac{4}{22}\cdot\left(\frac{x^{14}}{x^6}\right)\c  dot\left(\frac{w^{24}}{w^{30}}\right)\cdot\left(\f  rac{1}{z}\right)

    Do you think you can simplify this now?
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  3. #3
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    Thanks, Chris

    I got this answer:

    -2x^8w^6
    11z

    but my answers give me w^-6 "under the line"
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  4. #4
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by Elli View Post
    Thanks, Chris

    I got this answer:

    -2x^8w^6
    11z

    but my answers give me w^-6 "under the line"
    Note that \frac{w^{24}}{w^{30}}=w^{24-30}=w^{-6}=\frac{1}{w^6}
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  5. #5
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    so, how do you know when it goes "underline" or above?

    the w6
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  6. #6
    A riddle wrapped in an enigma
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    Quote Originally Posted by Elli View Post
    so, how do you know when it goes "underline" or above?

    the w6
    Hello Elli,

    When you have a variable with exponent in the numerator and same variable with exponent in the denominator, subtract the exponents (numerator exponent - denominator exponent).

    If the result is positive, leave the variable with the new exponent in the numerator. If the exponent is negative, put the variable with new exponent in the denominator.

    See Chris's last example.

    \frac{w^{24}}{w^{30}}=w^{-6}=\frac{1}{w^6}

    When he subtracted 24-30, the result was -6. So he put the w^6 in the denominator.
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