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Math Help - clarify something with this expression

  1. #1
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    clarify something with this expression

    in this expression

    <br />
\frac{\frac{-3h}{5(10+3h)}}{h}<br />

    can i do this

     <br />
\frac{\frac{-3h}{5(10+3h)}}{\frac{h}{1}} <br />

     <br />
\frac{-3h}{5(10+3h)} \cdot {\frac{1}{h}} <br />

     <br />
\frac{-3h}{5h(10+3h)}<br />

    can that be done to move the "h" around ??
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  2. #2
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    Quote Originally Posted by jvignacio View Post
    in this expression

    <br />
\frac{\frac{-3h}{5(10+3h)}}{h}<br />

    can i do this

     <br />
\frac{\frac{-3h}{5(10+3h)}}{\frac{h}{1}} <br />

     <br />
\frac{-3h}{5(10+3h)} \cdot {\frac{1}{h}} <br />

     <br />
\frac{-3h}{5h(10+3h)}<br />

    can that be done to move the "h" around ??
    Sure can. Now you can cancel the h in your last step.

     <br />
 \frac{-3}{5(10+3h)}<br />
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