in this expression

$\displaystyle

\frac{\frac{-3h}{5(10+3h)}}{h}

$

can i do this

$\displaystyle

\frac{\frac{-3h}{5(10+3h)}}{\frac{h}{1}}

$

$\displaystyle

\frac{-3h}{5(10+3h)} \cdot {\frac{1}{h}}

$

$\displaystyle

\frac{-3h}{5h(10+3h)}

$

can that be done to move the "h" around ??