write [1/(x-3)]-[1/(x-2)] as a single fraction with no common factors plse check for me my answer: My ans10-3x)/(x^2 -5*x + 6)
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Originally Posted by Faz write [1/(x-3)]-[1/(x-2)] as a single fraction with no common factors plse check for me my answer: My ans10-3x)/(x^2 -5*x + 6) $\displaystyle \frac{1}{x-3} - \frac{1}{x-2}$ $\displaystyle \frac{(x-2)}{(x-2)(x-3)} - \frac{(x-3)}{(x-2)(x-3)}$ $\displaystyle \frac{(x-2) - (x-3)}{(x-2)(x-3)}$ $\displaystyle \frac{x - 2 - x + 3}{(x-2)(x-3)}$ $\displaystyle \frac{1}{(x-2)(x-3)}$
[1/(x-3)]-[4/(x-2)].....sorry the second part should have a 4 and not 1/x-2 my mistake its a typo
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