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Math Help - single fraction

  1. #1
    Faz
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    single fraction

    write [1/(x-3)]-[1/(x-2)] as a single fraction with no common factors

    plse check for me my answer:
    My ans10-3x)/(x^2 -5*x + 6)
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  2. #2
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    Quote Originally Posted by Faz View Post
    write [1/(x-3)]-[1/(x-2)] as a single fraction with no common factors

    plse check for me my answer:
    My ans10-3x)/(x^2 -5*x + 6)
    \frac{1}{x-3} - \frac{1}{x-2}

    \frac{(x-2)}{(x-2)(x-3)} - \frac{(x-3)}{(x-2)(x-3)}

    \frac{(x-2) - (x-3)}{(x-2)(x-3)}

    \frac{x - 2 - x + 3}{(x-2)(x-3)}

    \frac{1}{(x-2)(x-3)}
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  3. #3
    Faz
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    fraction typo

    [1/(x-3)]-[4/(x-2)].....sorry the second part should have a 4 and not
    1/x-2 my mistake its a typo
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