# single fraction

• November 25th 2008, 06:16 AM
Faz
single fraction
write [1/(x-3)]-[1/(x-2)] as a single fraction with no common factors

plse check for me my answer:
My ans:(10-3x)/(x^2 -5*x + 6)
• November 25th 2008, 06:37 AM
skeeter
Quote:

Originally Posted by Faz
write [1/(x-3)]-[1/(x-2)] as a single fraction with no common factors

plse check for me my answer:
My ans:(10-3x)/(x^2 -5*x + 6)

$\frac{1}{x-3} - \frac{1}{x-2}$

$\frac{(x-2)}{(x-2)(x-3)} - \frac{(x-3)}{(x-2)(x-3)}$

$\frac{(x-2) - (x-3)}{(x-2)(x-3)}$

$\frac{x - 2 - x + 3}{(x-2)(x-3)}$

$\frac{1}{(x-2)(x-3)}$
• November 25th 2008, 06:50 AM
Faz
fraction typo
[1/(x-3)]-[4/(x-2)].....sorry the second part should have a 4 and not
1/x-2 my mistake its a typo