Please help me in anyway figure these out, I have a test tomorrow!
Solve the equation:
8^x+1=6
So far I have:
(x+1)log8 = log6
= xlog8 + 1log8 = log6
Do I subtract the 1log8 from both sides next?
Really confused so any help would be greatly appreciated!
i have some more-or-less similar log problems. could you help me out as well? http://www.mathhelpforum.com/math-he...ogarithms.html