Math Help - Help with Logarithmic Equations

1. Help with Logarithmic Equations

Please help me in anyway figure these out, I have a test tomorrow!

Solve the equation:
8^x+1=6

So far I have:
(x+1)log8 = log6
= xlog8 + 1log8 = log6

Do I subtract the 1log8 from both sides next?
Really confused so any help would be greatly appreciated!

2. Originally Posted by epetrik
Please help me in anyway figure these out, I have a test tomorrow!

Solve the equation:
8^x+1=6

So far I have:
(x+1)log8 = log6
= xlog8 + 1log8 = log6

Do I subtract the 1log8 from both sides next?
Really confused so any help would be greatly appreciated!
Here's the way to go about this.

$8^{x+1}=6$

$(x+1)\log 8=\log 6$

$x+1=\frac{\log 6}{\log 8}$

$x=\frac{\log 6}{\log 8}-1$

3. Originally Posted by masters
Here's the way to go about this.

$8^{x+1}=6$

$(x+1)\log 8=\log 6$

$x+1=\frac{\log 6}{\log 8}$

$x=\frac{\log 6}{\log 8}-1$
i have some more-or-less similar log problems. could you help me out as well? http://www.mathhelpforum.com/math-he...ogarithms.html

4. Thank you!!