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Thread: Help with Logarithmic Equations

  1. November 24th 2008, 02:48 PM #1
    epetrik
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    Help with Logarithmic Equations

    Please help me in anyway figure these out, I have a test tomorrow!

    Solve the equation:
    8^x+1=6

    So far I have:
    (x+1)log8 = log6
    = xlog8 + 1log8 = log6

    Do I subtract the 1log8 from both sides next?
    Really confused so any help would be greatly appreciated!
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  2. November 24th 2008, 03:09 PM #2
    masters
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    He's dead, Jim
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    Quote Originally Posted by epetrik View Post
    Please help me in anyway figure these out, I have a test tomorrow!

    Solve the equation:
    8^x+1=6

    So far I have:
    (x+1)log8 = log6
    = xlog8 + 1log8 = log6

    Do I subtract the 1log8 from both sides next?
    Really confused so any help would be greatly appreciated!
    Here's the way to go about this.

    8^{x+1}=6

    (x+1)\log 8=\log 6

    x+1=\frac{\log 6}{\log 8}

     x=\frac{\log 6}{\log 8}-1
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  3. November 24th 2008, 03:19 PM #3
    guywhohatesmath
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    Quote Originally Posted by masters View Post
    Here's the way to go about this.

    8^{x+1}=6

    (x+1)\log 8=\log 6

    x+1=\frac{\log 6}{\log 8}

    x=\frac{\log 6}{\log 8}-1
    i have some more-or-less similar log problems. could you help me out as well? http://www.mathhelpforum.com/math-he...ogarithms.html
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  4. November 24th 2008, 04:45 PM #4
    epetrik
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    Thank you!!
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