is $\displaystyle x^2+4x$ equal to x= ±√4

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- Nov 23rd 2008, 01:43 PM~berserkAlgebra Prob.
is $\displaystyle x^2+4x$ equal to x= ±√4

- Nov 23rd 2008, 02:04 PMskeeter
depends on what $\displaystyle x^2 + 4x$ is equal to ... did you leave that part out?

- Nov 23rd 2008, 02:16 PM~berserk
well the original problem is this: http://img149.imageshack.us/img149/3725/19497986mw6.jpg

i am trying to get the factored forms for the top and bottom so i can use sign analysis to determine the answer(s)

maybe it did not show up for you but it says x= plus or minus the squarerootof 4 for the first post - Nov 23rd 2008, 02:20 PMskeeter
$\displaystyle \frac{n^2+4n+4}{n^2+4n} > 0$

$\displaystyle \frac{(n+2)^2}{n(n+4)} > 0$

critical values are $\displaystyle n = -2$, $\displaystyle n = 0$, and $\displaystyle n = -4$

now do your sign analysis.