Results 1 to 3 of 3

Math Help - Indices help

  1. #1
    Newbie
    Joined
    Nov 2008
    Posts
    2

    Indices / powers help

    This is probably quite simple but I am not sure where to start, any help appreciated!

    [(4a^-2)^-2]^-1
    Last edited by Sqrtof-1isi; November 23rd 2008 at 03:10 PM. Reason: .
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Nov 2008
    Posts
    47
    Let's use the formula: x^-n= 1/(x^n). We shall start with outer exponent: 1/[(4a^-2)^-2]^1=1/(4a^-2)^-2. Follow the same formula = 1/{1/(4a^-2)^2. Fraction divide by fraction= fraction multiply by reciprocal; (4a^-2)^2, let's simplify this; 16a^-4, and one more negative exponent: 16/a^4
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Nov 2008
    Posts
    2

    Thank you

    Thanks this one had me stumped with all the extra exponents
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Indices
    Posted in the Algebra Forum
    Replies: 2
    Last Post: November 9th 2009, 01:18 AM
  2. indices
    Posted in the Algebra Forum
    Replies: 6
    Last Post: November 8th 2009, 07:01 AM
  3. Indices
    Posted in the Algebra Forum
    Replies: 2
    Last Post: November 7th 2009, 04:52 AM
  4. indices
    Posted in the Algebra Forum
    Replies: 1
    Last Post: January 28th 2009, 05:26 AM
  5. INDICES
    Posted in the Algebra Forum
    Replies: 6
    Last Post: October 28th 2008, 12:34 PM

Search Tags


/mathhelpforum @mathhelpforum