# Exponential and Logarithmic Equations

• Nov 23rd 2008, 01:28 PM
contristo
Exponential and Logarithmic Equations
Hi. I am extremely confused with this question:

Express the function N(r) = -5000 ln r in its equivalent exponential form. Give a complete explanation of how an exponential equation is related to its equivalent logarithmic equation.

I am curious as to how to convert the logarithmic equation to its equivalent exponential equation.
I was assigned this today and I have a test tomorrow on similar material.

Any help would be greatly appreciated. Thanks.
• Nov 23rd 2008, 01:31 PM
skeeter
if $a = \log_b{c}$ , then $b^a = c$
• Nov 23rd 2008, 01:34 PM
contristo
thanks, but how would I be able to convert N(r) = -5000 ln r to http://www.mathhelpforum.com/math-he...b6ab0279-1.gif? what does A, B, and C equal? Thanks
• Nov 23rd 2008, 01:50 PM
skeeter
$-\frac{N}{5000} = \log_e{r}$
• Nov 23rd 2008, 02:02 PM
contristo
so, let me get this straight:

The function N(r) = -5000 ln r is equivalent to the exponential form of e^-(N/5000) = r. This is gathered through several steps. First, keeping in mind that a = logbc = b^a = c, one gains the knowledge that –(N/5000) is equal to loger when applied to the logarithmic equation of N(r) = -5000 ln r.

Is this right?
• Nov 23rd 2008, 02:09 PM
skeeter
Quote:

Originally Posted by contristo
so, let me get this straight:

The function N(r) = -5000 ln r is equivalent to the exponential form of e^-(N/5000) = r.

Is this right?

yes
• Nov 23rd 2008, 02:11 PM
contristo
thank you. I appreciate the help.