Hi,

I don't think I'm getting the correct roots for this equation...

3x2(squared)- 2x- 6 = 0

That should read 3xsquared.

I had to use the b +/- formula and I'm getting x= 1.79 or x= -1.12

That can't be right???

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- Nov 23rd 2008, 01:21 PMLarianneQuadratic Equation
Hi,

I don't think I'm getting the correct roots for this equation...

3x2(squared)- 2x- 6 = 0

That should read 3xsquared.

I had to use the b +/- formula and I'm getting x= 1.79 or x= -1.12

That can't be right??? - Nov 23rd 2008, 01:30 PMeuclid2
- Nov 23rd 2008, 01:34 PMo_O
Let's format that a little better: $\displaystyle x = \frac{b \pm \sqrt{b^2 - 4ac}}{2a}$

Why don't you think that's right? You rounded off to a few decimal places which will throw off your answer a little bit but it is correct (again, rounded of course) - Nov 23rd 2008, 01:35 PMLarianne
- Nov 23rd 2008, 01:43 PMeuclid2
- Nov 23rd 2008, 01:43 PMLarianne
- Nov 23rd 2008, 01:44 PMLarianne
- Nov 23rd 2008, 01:45 PMeuclid2