Questions can be found here:
http://www.freewebs.com/kgpretty/math.JPG
I attempted #4.. can you use 4 .. determinants? to solve the equation like:
For #7, I've think I've got that covered. Just tell me.. would the augmented matrix be:Code:x|k l| -a|l m| x|k l| -a|l m| |m n| |n o| |o k| |n o|
|log1 log1 log1|0|
to represent the first row?
or |1 1 1|0|, where log is factorised out?
For all the other questions.. I simply don't know what to do
For your other problem.
Do my excersice.
Show that the determinant below is always zero.
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Once you have done that you can use the fact, x,y,z>0
log(2x)=log2 +log x
log(2y)=log2 +log y
log(2z)=log2 +log z
log(3x)=log3+log x
log(3y)=log3+log y
log(3z)=log3+log z
Let,
a=log x
b=log y
c=log z
Then you end with,
Then use that result.Code:a b c a+log 2 b+log 2 c+log 2 a+log 3 b+log 3 c+log 3