Questions can be found here:
I attempted #4.. can you use 4 .. determinants? to solve the equation like:
For #7, I've think I've got that covered. Just tell me.. would the augmented matrix be:Code:x|k l| -a|l m| x|k l| -a|l m| |m n| |n o| |o k| |n o|
|log1 log1 log1|0|
to represent the first row?
or |1 1 1|0|, where log is factorised out?
For all the other questions.. I simply don't know what to do
For your other problem.
Do my excersice.
Show that the determinant below is always zero.
Once you have done that you can use the fact, x,y,z>0
log(2x)=log2 +log x
log(2y)=log2 +log y
log(2z)=log2 +log z
Then you end with,
Then use that result.Code:a b c a+log 2 b+log 2 c+log 2 a+log 3 b+log 3 c+log 3