# Formulating an equation

• Nov 22nd 2008, 03:37 PM
Franc
Formulating an equation
A man goes to the bank with a \$260 check.
He tells the teller he needs 3 times the amount of dollar bills
as much as 5 dollar bills and half as much of the 5 dollar bills
in 10 dollar bills.

Need desparate help to solve this.
• Nov 22nd 2008, 03:49 PM
mr fantastic
Quote:

Originally Posted by Franc
A man goes to the bank with a \$260 check.
He tells the teller he needs 3 times the amount of dollar bills
as much as 5 dollar bills and half as much of the 5 dollar bills
in 10 dollar bills.

Need desparate help to solve this.

x = number of \$1 bills, y = number of \$5 bills, z = number of \$10 bills.

Solve simultaneously:

x = 3y .... (1)

y = z/2 .... (2)

x + y + z = 260 .... (3)
• Nov 22nd 2008, 03:54 PM
masters
Quote:

Originally Posted by Franc
A man goes to the bank with a \$260 check.
He tells the teller he needs 3 times the amount of dollar bills
as much as 5 dollar bills and half as much of the 5 dollar bills
in 10 dollar bills.

Need desparate help to solve this.

This is what I think you have stated:

Let x = number of \$5 bills

Let 3x = number of \$1 bills

Let (1/2) x = number of \$10 bills

x + 3x + (1/2) x = 260

You should now be able to complete.

Edit: I'm gettin' 'em in too slowly tonight!
• Nov 22nd 2008, 04:05 PM
tdschool
Let's be x-number of \$5 bills, then number of \$1 bills will be 3x, and \$10 bills x/2. Now let's count the money; \$5 *x+ \$1 * 3x+ \$10 * x/2=260; 5x+3x+5x=260; 13x=260; x=20. Answer: there are 20 \$5 bills, 60 \$1 bills, 10 \$10 bills. Checking: 20*5+60+10*10=260