a) LogP = 2 + logx b) LogM = 1.477 - x Help!
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Originally Posted by bickitrainer a) LogP = 2 + logx b) LogM = 1x477 - x Help! Hey mate, for (a) log(P) = 2 + log(x) log(P) - log(x) = 2 log(P/x) = 2 ( log(A/B) = log(A) - log(B) ) P/x = 100 (10^n = b --> log(b) = n) x = 100/P Hope this helps, Davi
Last edited by mr fantastic; November 22nd 2008 at 03:41 AM. Reason: bickitrainer double posted (a) when re-posting a correct version of (b). David24 answered the original post.
Originally Posted by bickitrainer a) LogP = 2 + logx b) LogM = 1.477 - x Help! I assume that the base of the logarithms is 10. If so: I assume that . If so:
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