Write the following equations without logarithms:

**bickitrainer** · November 21st 2008, 07:46 PM

a) LogP = 2 + logx

b) LogM = 1.477 - x

Help!

**David24** · November 21st 2008, 08:11 PM

Originally Posted by bickitrainer

a) LogP = 2 + logx

b) LogM = 1x477 - x

Help!

Hey mate,

for (a)
log(P) = 2 + log(x)
log(P) - log(x) = 2
log(P/x) = 2 ( log(A/B) = log(A) - log(B) )
P/x = 100 (10^n = b --> log(b) = n)
x = 100/P

Hope this helps,

Davi

**earboth** · November 21st 2008, 09:57 PM

Originally Posted by bickitrainer

a) LogP = 2 + logx

b) LogM = 1.477 - x

Help!

I assume that the base of the logarithms is 10. If so:

$\log(P)=2+\log(x)~\implies~10^{\log(P)}=10^{2+\log (x)}~\implies~P=100\cdot x$

I assume that $1.477 = \log(30)$ . If so:

$\log(M)=1.477-x~\implies~10^{\log(M)}=10^{1.477-x}~\implies~ M=\dfrac{10^{1.477}}{10^x}\implies~ M=\dfrac{30}{10^x}$

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