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Math Help - Simplify

  1. #1
    Junior Member turbod15b's Avatar
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    Simplify

    how do you simplify this



    and make C the subject

    thanks
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  2. #2
    A riddle wrapped in an enigma
    masters's Avatar
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    Hello Turbo,

    Simplify: (3x)\left(\frac{10y^3x}{5y^3}-x\right)+\left(\frac{12x^4y^2}{3x^4y}-2y\right)(2y)

    3x(2x-x)+(4y-2y)(2y)

    3x(x)+2y(2y)

    \boxed{3x^2+4y^2}


    Solve for C:

    Q=\frac{1}{R}\sqrt{\frac{L}{C}}

    RQ=\sqrt{\frac{L}{C}}

    (RQ)^2=\frac{L}{C}

    C(RQ)^2=L

    \boxed{C=\frac{L}{(RQ)^2}}
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  3. #3
    Junior Member turbod15b's Avatar
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    thanks alot
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  4. #4
    Senior Member Twig's Avatar
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    hi

    Hi there

    I donŽt know what level youŽre at, so I donŽt know how much I should take
    for granted that you know.
    Can you see the "most obvious" simplifications you make?
    Like shorten out the y^3 terms in the first fraction?

    When you have factors like this for exampl: \frac{10x^3y^2}{5x^3y}
    You see that the number ten is actually composed by two prime numbers, namely 2 and 5.
    2 \cdot 5 = 10
    In the same way, x^3 = x \cdot x \cdot x

    So youŽll end up with(using my example):
    \frac{10x^3y^2}{5x^3y} = 2y
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  5. #5
    Junior Member turbod15b's Avatar
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    just forgot to mention for the second one

    calculate the value of capacitence C in farads

    C in farads
    Indunctance L = 0.2H
    Resistance R = 50 ohms
    Charge Q = 15C

    so if
    C = L/(RQ)2

    C= 0.2/(50x15)2= 0.000000355
    correct?
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