First attempt:

$\displaystyle 4a^2+2a+\frac{1}{4}$ → Original Problem

$\displaystyle 2[2a^2+a+\frac{1}{8}]$

...but I can't keep on.

So I tried again:

$\displaystyle 4a^2+2a+\frac{1}{4}$

$\displaystyle 4a^2+2a+\frac{1}{2^2}$

$\displaystyle 4a^2+2a+1^{-2}$

...but then again, this is quite likely to be mistaken.

Please I need some help.