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Thread: Algebra

  1. Nov 21st 2008, 02:27 AM #1
    dankelly07
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    Algebra

    Ok any ideas on a quick way of cancelling expressions like this?

    <br /> \frac{{2\sqrt {5x - 1} - \frac{{5(2x + 7)}}<br /> {{2\sqrt {5x - 1} }}}}<br /> {{(5x - 1)}}<br />

    I'm just getting a bit lost..
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  2. Nov 21st 2008, 02:37 AM #2
    Chop Suey
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    Multiply the expression by \frac{\sqrt{5x-1}}{\sqrt{5x-1}}. See where that gets you
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  3. Nov 21st 2008, 02:56 AM #3
    dankelly07
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    This right..?

    <br /> \frac{{\frac{{2\sqrt {5x - 1} }}<br /> {1} - \frac{{5(2x + 7)}}<br /> {{2\sqrt {5x - 1} }}}}<br /> {{(5x - 1)}}<br />

    <br /> \begin{gathered}<br /> \frac{{\frac{{2\sqrt {5x - 1} (2\sqrt {5x - 1} )}}<br /> {{2\sqrt {5x - 1} }} - \frac{{(1)5(2x + 7)}}<br /> {{2\sqrt {5x - 1} }}}}<br /> {{(5x - 1)}} \hfill \\<br /> \hfill \\<br /> \frac{{\frac{{5x - 20 - 7x + 7 - 10x - 7}}<br /> {{2\sqrt {5x - 1} }}}}<br /> {{5x - 1}} \hfill \\ <br /> \end{gathered} <br />

    <br /> \frac{{\frac{{ - 12x - 20}}<br /> {{2\sqrt {5x - 1} }}}}<br /> {{5x - 1}}<br />

    Also at this stage I have read conflicting Ideas...

    Is a/b/c = c * a / b
    OR
    a/b/c = a / b*c

    How do you know which one to choose..??

    .......
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  4. Nov 25th 2008, 02:21 AM #4
    dankelly07
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    Can anyone help?..
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« College Algebra, URGENT! Please help. Need submitted by 10:45 or I fail my math class | Quadratic Enquiry »

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