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Thread: Algebra

  1. #1
    Member
    Joined
    Sep 2007
    Posts
    76

    Algebra

    Ok any ideas on a quick way of cancelling expressions like this?

    $\displaystyle
    \frac{{2\sqrt {5x - 1} - \frac{{5(2x + 7)}}
    {{2\sqrt {5x - 1} }}}}
    {{(5x - 1)}}
    $

    I'm just getting a bit lost..
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  2. #2
    Super Member
    Joined
    Jun 2008
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    792
    Multiply the expression by $\displaystyle \frac{\sqrt{5x-1}}{\sqrt{5x-1}}$. See where that gets you
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  3. #3
    Member
    Joined
    Sep 2007
    Posts
    76
    This right..?

    $\displaystyle
    \frac{{\frac{{2\sqrt {5x - 1} }}
    {1} - \frac{{5(2x + 7)}}
    {{2\sqrt {5x - 1} }}}}
    {{(5x - 1)}}
    $

    $\displaystyle
    \begin{gathered}
    \frac{{\frac{{2\sqrt {5x - 1} (2\sqrt {5x - 1} )}}
    {{2\sqrt {5x - 1} }} - \frac{{(1)5(2x + 7)}}
    {{2\sqrt {5x - 1} }}}}
    {{(5x - 1)}} \hfill \\
    \hfill \\
    \frac{{\frac{{5x - 20 - 7x + 7 - 10x - 7}}
    {{2\sqrt {5x - 1} }}}}
    {{5x - 1}} \hfill \\
    \end{gathered}
    $

    $\displaystyle
    \frac{{\frac{{ - 12x - 20}}
    {{2\sqrt {5x - 1} }}}}
    {{5x - 1}}
    $

    Also at this stage I have read conflicting Ideas...

    Is a/b/c = c * a / b
    OR
    a/b/c = a / b*c

    How do you know which one to choose..??

    .......
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  4. #4
    Member
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    Sep 2007
    Posts
    76
    Can anyone help?..
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