Consider:

(8a) (b) (a)

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(b) (-8a^2) (-b)

Simplify:

(-1) (a^2-2) (b^1-2)

8 divide by -8 is -1, two a at numerator is a^2, then a^2-2

what about b? I have a minus b at the denominator, what would the final b be? a positive or negative? - I took the numerator b which is a positive.

(-1) (a^0) (b^-1)

(-1) (1) (b^-1)

-b^-1

The answer is b^-1.

I think I got my signs wrong and I don't know how to deal with the signs as in the case of b.

Please help to explain how to deal with the signs of b.

Thanks.