Results 1 to 2 of 2

Math Help - Logarithm

  1. #1
    Faz
    Faz is offline
    Banned
    Joined
    Nov 2008
    Posts
    46

    Logarithm

    Evaluate
    LOG 4 (with base 2) - log 2 (with base 2) + LOG 1 (with base 2)
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Banned
    Joined
    Aug 2008
    Posts
    530
    Quote Originally Posted by Faz View Post
    Evaluate
    LOG 4 (with base 2) - log 2 (with base 2) + LOG 1 (with base 2)
    \log_2 4 - \log_2 2 + \log_2 1

    =\log_2 2^2 - \log_2 2^1 + \log_2 2^0

    =2-1+0<br />

    =1<br />
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: July 18th 2011, 08:04 AM
  2. logarithm
    Posted in the Algebra Forum
    Replies: 3
    Last Post: July 17th 2010, 05:23 AM
  3. Logarithm #2
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: June 1st 2010, 06:29 AM
  4. Logarithm
    Posted in the Algebra Forum
    Replies: 6
    Last Post: September 17th 2009, 11:23 PM
  5. Logarithm
    Posted in the Algebra Forum
    Replies: 4
    Last Post: March 13th 2008, 11:05 AM

Search Tags


/mathhelpforum @mathhelpforum