Thread: order of operations

what is the correct order of operations to solve this


(3+3)(2)(3)^3+1

Originally Posted by fey

what is the correct order of operations to solve this


(3+3)(2)(3)^3+1

(6)(2)(3)^3+1
(6)(2)(3)(3)(3)+1
12(3)(3)(3)+1
36(3)(3)+1
108(3)+1
324+1
325

Originally Posted by fey

what is the correct order of operations to solve this


(3+3)(2)(3)^3+1

Just remember the order of operations:
Parentheses
Exponents
Division/Multiplication
Addition/Subtraction

Better known as PEMDAS

therefore
(3+3)(2)(3)^3+1
do parentheses: (6)(2)(3)^3 +1
do exponents: (6)(2)(27) + 1
do division/multiplication: 324 +1
do addition/subtraction: 325

BODMAS

Brackets
Of
Division
Multiplication
Addition
Subtraction

$\displaystyle (3+3)(2)(3)^3+1$

Make sure all brackets are worked out (notice the {3+3})

$\displaystyle (6)(2)(3)^3+1$

When you have a power ( $\displaystyle (3)^3$ ) understand that that power is tied to just naything before it in brackets, so since there's a bracket containing 3 before it, you cube that number

$\displaystyle 3^3$ = 27

So right now we're like this:

(6)(2)(27)+1

Addition is at the bottom of BODMAS, so that's kept for last

(6)(2)(27)
(12)(27)
324

But don't forget that little +1 at the end...
so 324 + 1 = 325

Practice using BODMAS, try making your own questions, and don't worry about getting it wrong, as long as you're trying, you'll improve greatly in mathematics

PEMDAS