1. ## Completing the square

Basically got coursework in due tomorrow (10% of final marks, kinda a homework sheet).

y=x^2+8x+1 <-- Complete the square and find the min point.

(x+4)^2-15=x^2+8x+1

Got: min point (-4,-15)
Just wondering if the x is a minus or not, because its squared (Above).

y=3x+6x+11 <-- Complete the square and find the min point.

Cheers! jD.

2. Originally Posted by Backlock
Basically got coursework in due tomorrow (10% of final marks, kinda a homework sheet).

Just wondering if the x is a minus or not, because its squared (Above).

Cheers! jD.
$\displaystyle y=(x+4)^2-15$

The vertex is (-4, -15), so the minimum is the y value. Minimum point is the vertex.

$\displaystyle y=3x^2+6x+11$
$\displaystyle y=3(x^2+2x+1)+11-3$
$\displaystyle y=3(x+1)^2+8$
3. Thanks alot, I ended up with $\displaystyle (1/3 , 8)$ Saved a me few marks