3(4x² -y² )-5(4x² +4xy+y² ) I done the 1st step which is 3(2x+y)(2x-y)-5(2x+y)² (2x+y)(3(2x-y))-5(2x+y) but then i cant facortise anymore after i take out the (2x+y)
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3(2x+y)(2x-y)-5(2x+y)²=(2x+y)[3(2x-y)-5(2x+y)]=(2x+y)[6x-3y-10x-5y]= =(2x+y)[-4x-8y]=-4(2x+y)(x+2y)
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