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Math Help - new to forums, and transforming formulas :D

  1. #1
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    new to forums, and transforming formulas :D

    could someone teach me a simple way for transforming formulas.
    i know how to do the simple transforming of formulas, but these kinds i get confused and stuck.

    examples.


    EDIT:
    1. a = v - u/t ; solve for u



    2. a = a + b + c + d/4 ; solve for b


    3. 2ax + 1 = ax + 5 ; solve for x


    4. m = x + y + z/3 solve for x


    5. D = a/2 (2t - 1) ; solve for a



    i wouldnt want the answers to these questions,
    just simple steps so i may remember to do them easily in the future.
    Last edited by flash670; November 19th 2008 at 12:46 PM.
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  2. #2
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    1. a = v - u
    ------
    t solve for u

    Answer:

    a=v-u
    a+u=v-u+u
    a+u=v+0
    a+u=v
    a+u-a=v-a
    u+a-a=v-a
    u+0=v-a
    u=v-a
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  3. #3
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    1. a = v - u
    ------
    t solve for u

    or
    a=(v-u)/t ?
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  4. #4
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    Unhappy

    I don't understand your equations, can you use Math editor?
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  5. #5
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    EDIT to post,
    sorry for bad equation.
    new to site..
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  6. #6
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    Quote Originally Posted by flash670 View Post
    could someone teach me a simple way for transforming formulas.
    i know how to do the simple transforming of formulas, but these kinds i get confused and stuck.

    examples.


    EDIT:
    1. a = v - u/t ; solve for u
    a=v-\frac{u}{t}

    Multiply everything by t in order to eliminate the fraction.

    at=tv-u

    Isolate -u by subtracting tv from both sides.

    at-tv=-u

    Multiply by -1 to solve for u.

    tv-at=u


    Quote Originally Posted by flash670 View Post
    2. a = a + b + c + d/4 ; solve for b
    a=a+b+c+\frac{d}{4}

    Subtract all terms except b for both sides

    a-a-c-\frac{d}{4}=b
    -c-\frac{d}{4}=b

    Quote Originally Posted by flash670 View Post
    3. 2ax + 1 = ax + 5 ; solve for x
    2ax+1=ax+5

    Group the x terms on the left by subtracting ax and 1 from both sides

    2ax-ax=5-1
    ax=6

    x=\frac{6}{a}

    Quote Originally Posted by flash670 View Post
    4. m = x + y + z/3 solve for x
    m=x+y+\frac{z}{3}

    Multiply all terms by 3 to eliminate the fraction.

    3m=3x+3y+z

    Subtract 3y and z from both sides

    3m-3y-z=3x

    Divide everything by 3

    \frac{3m-3y-z}{3}=x or m-y-\frac{z}{3}=x

    Quote Originally Posted by flash670 View Post

    5. D = a/2 (2t - 1) ; solve for a
    D=\frac{a}{2}\left(2t-1\right)

    Multiply everything by 2 to eliiminate the fraction.

    2D=a(2t-1)

    Divide both sides by 2t-1 to isolate a

    \frac{2D}{2t-1}=a
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