# Math Help - new to forums, and transforming formulas :D

1. ## new to forums, and transforming formulas :D

could someone teach me a simple way for transforming formulas.
i know how to do the simple transforming of formulas, but these kinds i get confused and stuck.

examples.

EDIT:
1. a = v - u/t ; solve for u

2. a = a + b + c + d/4 ; solve for b

3. 2ax + 1 = ax + 5 ; solve for x

4. m = x + y + z/3 solve for x

5. D = a/2 (2t - 1) ; solve for a

i wouldnt want the answers to these questions,
just simple steps so i may remember to do them easily in the future.

2. 1. a = v - u
------
t solve for u

a=v-u
a+u=v-u+u
a+u=v+0
a+u=v
a+u-a=v-a
u+a-a=v-a
u+0=v-a
u=v-a

3. 1. a = v - u
------
t solve for u

or
a=(v-u)/t ?

4. I don't understand your equations, can you use Math editor?

5. EDIT to post,
new to site..

6. Originally Posted by flash670
could someone teach me a simple way for transforming formulas.
i know how to do the simple transforming of formulas, but these kinds i get confused and stuck.

examples.

EDIT:
1. a = v - u/t ; solve for u
$a=v-\frac{u}{t}$

Multiply everything by t in order to eliminate the fraction.

$at=tv-u$

Isolate -u by subtracting tv from both sides.

$at-tv=-u$

Multiply by -1 to solve for u.

$tv-at=u$

Originally Posted by flash670
2. a = a + b + c + d/4 ; solve for b
$a=a+b+c+\frac{d}{4}$

Subtract all terms except b for both sides

$a-a-c-\frac{d}{4}=b$
$-c-\frac{d}{4}=b$

Originally Posted by flash670
3. 2ax + 1 = ax + 5 ; solve for x
$2ax+1=ax+5$

Group the x terms on the left by subtracting ax and 1 from both sides

$2ax-ax=5-1$
$ax=6$

$x=\frac{6}{a}$

Originally Posted by flash670
4. m = x + y + z/3 solve for x
$m=x+y+\frac{z}{3}$

Multiply all terms by 3 to eliminate the fraction.

$3m=3x+3y+z$

Subtract 3y and z from both sides

$3m-3y-z=3x$

Divide everything by 3

$\frac{3m-3y-z}{3}=x$ or $m-y-\frac{z}{3}=x$

Originally Posted by flash670

5. D = a/2 (2t - 1) ; solve for a
$D=\frac{a}{2}\left(2t-1\right)$

Multiply everything by 2 to eliiminate the fraction.

$2D=a(2t-1)$

Divide both sides by 2t-1 to isolate a

$\frac{2D}{2t-1}=a$