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Math Help - Exponential Equation Help

  1. #1
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    Exponential Equation Help

    Hi,
    This is my first post here and am having trouble with a particular question. Any help would be apprecaited. Here it is:

    solve:
    ln,squareroot of x-2=1

    or
    ln/x-2=1

    I can't figure out how to do a square root symbol with out the equation editor.

    Thanks I hope you understand this
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  2. #2
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    you put both in squared and you will get x-2=1


    x=1+2
    x=3
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  3. #3
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    There is a mistake. I understand ln is natural log.
    ln(sqr(x-2))=1 1=ln(e), ln sqr(x-2)=ln(e) ; sqr( x-2)=e; x-2=e^2 x=e^2+2= 2.7183^2+2=9.38915....or 9.39
    Last edited by tdschool; November 18th 2008 at 04:56 PM.
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  4. #4
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    Quote Originally Posted by hondaman74 View Post
    Hi,
    This is my first post here and am having trouble with a particular question. Any help would be apprecaited. Here it is:

    solve:
    ln,squareroot of x-2=1

    or
    ln/x-2=1
    \ln\sqrt{x-2} = 1

    \frac{1}{2}\ln(x-2) = 1

    \ln(x-2) = 2

    x-2 = e^2

    x = e^2 + 2


    what is the 2nd equation ?

    \ln{x} - 2 = 1

    \ln(x-2) = 1

    \frac{\ln(something)}{x-2} = 1

    ???
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  5. #5
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    Skeeter, thank you very much, with som help with my phone tutor we came up with the same answer. I really appreciate the help. how did you add the equation editor or be able ot show hte problem. I could not figure it out.
    Keith
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