1. ## Exponential Equation Help

Hi,
This is my first post here and am having trouble with a particular question. Any help would be apprecaited. Here it is:

solve:
ln,squareroot of x-2=1

or
ln/x-2=1

I can't figure out how to do a square root symbol with out the equation editor.

Thanks I hope you understand this

2. you put both in squared and you will get x-2=1

x=1+2
x=3

3. There is a mistake. I understand ln is natural log.
ln(sqr(x-2))=1 1=ln(e), ln sqr(x-2)=ln(e) ; sqr( x-2)=e; x-2=e^2 x=e^2+2= 2.7183^2+2=9.38915....or 9.39

4. Originally Posted by hondaman74
Hi,
This is my first post here and am having trouble with a particular question. Any help would be apprecaited. Here it is:

solve:
ln,squareroot of x-2=1

or
ln/x-2=1
$\displaystyle \ln\sqrt{x-2} = 1$

$\displaystyle \frac{1}{2}\ln(x-2) = 1$

$\displaystyle \ln(x-2) = 2$

$\displaystyle x-2 = e^2$

$\displaystyle x = e^2 + 2$

what is the 2nd equation ?

$\displaystyle \ln{x} - 2 = 1$

$\displaystyle \ln(x-2) = 1$

$\displaystyle \frac{\ln(something)}{x-2} = 1$

???

5. Skeeter, thank you very much, with som help with my phone tutor we came up with the same answer. I really appreciate the help. how did you add the equation editor or be able ot show hte problem. I could not figure it out.
Keith