The roots of the equation ax^2 + 4x = –2 are real, rational, and equal when a has a value of (1) 1 (3) 3 (2) 2 (4) 4
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Originally Posted by magentarita The roots of the equation ax^2 + 4x = –2 are real, rational, and equal when a has a value of (1) 1 (3) 3 (2) 2 (4) 4 If a=1, then has irrational roots. (Use quadratic formula) If a=2, then . Dividing all terms by 2, we have: . Now factor to get: . We have 2 equal roots (double root) at x=-1 If you test a=3 and a-4, you'll see that they have imaginary roots.
Originally Posted by masters If a=1, then has irrational roots. (Use quadratic formula) If a=2, then . Dividing all terms by 2, we have: . Now factor to get: . We have 2 equal roots (double root) at x=-1 If you test a=3 and a-4, you'll see that they have imaginary roots. A wonderful repy as always.
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