The roots of the equationax^2 + 4x= –2 are real, rational, and equal whenahas a value of

(1) 1 (3) 3

(2) 2 (4) 4

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- Nov 17th 2008, 10:18 PMmagentaritaRoots of the EquationThe roots of the equation
*ax^*2 + 4*x*= –2 are real, rational, and equal when*a*has a value of

(1) 1 (3) 3

(2) 2 (4) 4

- Nov 18th 2008, 01:54 PMmasters
If

**a=1**, then $\displaystyle x^2+4x+2=0$ has irrational roots. (Use quadratic formula)

If**a=2**, then $\displaystyle 2x^2+4x+2=0$. Dividing all terms by**2**, we have:

$\displaystyle x^2+2x+1=0$. Now factor to get:

$\displaystyle (x+1)(x+1)=0$.__We have__**2**equal roots (double root) at__x=-1__

If you test a=3 and a-4, you'll see that they have imaginary roots.

- Nov 18th 2008, 09:30 PMmagentaritaok...........