Find the possible values of k-

$k^4-k^2-12=0$

2. Originally Posted by greghunter
Find the possible values of k-

$k^4-k^2-12=0$
Use the substitution $y = k^2$. Your equation becomes:

$y^2-y-12=0$

Solve for y.
Re-substitute and solve for k.

(For the records: If you are looking for real values I've got k = -2 or k = 2)