Find the possible values of k- $\displaystyle k^4-k^2-12=0$
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Originally Posted by greghunter Find the possible values of k- $\displaystyle k^4-k^2-12=0$ Use the substitution $\displaystyle y = k^2$. Your equation becomes: $\displaystyle y^2-y-12=0$ Solve for y. Re-substitute and solve for k. (For the records: If you are looking for real values I've got k = -2 or k = 2)
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