Solve for x:
e^(2x)+2e^x+15=0
Thanks
if you are not doing complex analysis, then just say there is no solution and move on.
otherwise $\displaystyle \ln z = \ln |z| + i \text{Arg}z$
where $\displaystyle z \in \mathbb{C}$ and $\displaystyle - \pi < \text{Arg}z \le \pi$
that gives the principal logarithm, which is usually what they want