Solve for x:

e^(2x)+2e^x+15=0

Thanks

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- November 16th 2008, 05:20 PMLinnusShould be a easy problem...
Solve for x:

e^(2x)+2e^x+15=0

Thanks - November 16th 2008, 05:22 PMJhevon
- November 16th 2008, 05:32 PMLinnus
So I got 2 imaginary numbers for y...

e^x= a imaginary number...

How do you ln an imaginary number? - November 16th 2008, 05:34 PMJhevon