Here is the equation: [3 2 -1] [-2 0 2] multiplied by [2 x] [-1 4] [3 y] equals [1 0] [2 4] instructions call to solve for x and y but i can seem to be able to find them, please help me. . .
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Originally Posted by runner940 Here is the equation: [3 2 -1] [-2 0 2] multiplied by [2 x] [-1 4] [3 y] equals [1 0] [2 4] instructions call to solve for x and y but i can seem to be able to find them, please help me. . . Once you multiply the matrices together, compare the values of the elements... Multiplying the two matrices together yields the equation In comparing the elements, the only system that we need to solve is Do you think that you can find x and y now? --Chris
when you multiply those matrices,you get 2*2 as dimensions of the answer which is 1 3x-y+8 = 1 0 2 -2x+2y = 2 4 which means that 3x-y=-8 and -2x+2y=4 -x+y=2 y=x+2 3x-x-2=2 2x=4 x=2 y=2+2=4 S=(2,4)
Originally Posted by franckherve1 when you multiply those matrices,you get 2*2 as dimensions of the answer which is 1 3x-y+8 = 1 0 2 -2x+2y = 2 4 which means that 3x-y=-8 and -2x+2y=4 -x+y=2 y=x+2 3x-x-2=2 2x=4 x=2 y=2+2=4 S=(2,4) This solution is difficult to follow. The answer given is incorrect.
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