Here is the equation:
[3 2 -1]
[-2 0 2]
multiplied by
[2 x]
[-1 4]
[3 y]
equals
[1 0]
[2 4]
instructions call to solve for x and y but i can seem to be able to find them, please help me. . .
Once you multiply the matrices together, compare the values of the elements...
$\displaystyle \begin{bmatrix}3&2&-1\\-2&0&2\end{bmatrix}\begin{bmatrix}2&x\\-1&4&\\3&y\end{bmatrix}=\begin{bmatrix}1&0\\2&4\end {bmatrix}$
Multiplying the two matrices together yields the equation $\displaystyle \begin{bmatrix}1&3x+8-y\\2&-2x+2y\end{bmatrix}=\begin{bmatrix}1&0\\2&4\end{bma trix}$
In comparing the elements, the only system that we need to solve is $\displaystyle \left\{\begin{array}{rcrcr}3x&-&y&=&-8\\-x&+&y&=&2\end{array}\right.$
Do you think that you can find x and y now?
--Chris