Here is the equation:

[3 2 -1]

[-2 0 2]

multiplied by

[2 x]

[-1 4]

[3 y]

equals

[1 0]

[2 4]

instructions call to solve for x and y but i can seem to be able to find them, please help me. . . (Bear)

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- Nov 16th 2008, 11:49 AMrunner940Need help solving for 'x' and 'y' in matrices...
Here is the equation:

[3 2 -1]

[-2 0 2]

multiplied by

[2 x]

[-1 4]

[3 y]

equals

[1 0]

[2 4]

instructions call to solve for x and y but i can seem to be able to find them, please help me. . . (Bear) - Nov 16th 2008, 12:10 PMChris L T521
- Nov 16th 2008, 12:14 PMfranckherve1
when you multiply those matrices,you get 2*2 as dimensions of the answer which is

1 3x-y+8 = 1 0

2 -2x+2y = 2 4

which means that 3x-y=-8 and -2x+2y=4

-x+y=2 y=x+2

3x-x-2=2

2x=4

x=2

y=2+2=4

S=(2,4) - Nov 18th 2008, 07:05 PMmr fantastic