simplify fraction

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November 15th 2008, 06:44 PM
Worthey1987

simplify fraction

Hey, this one's probably real simple, but I'm stuck.

I'd like to see the work and answer for performing the operations and simplifying this:

x-y - x+y
x+y x-y
x+y - x-y
x-y x+y

I'd appreciate any help. Like I said I'm sure it's easy, I'm just stuck.

-Worthey1987
November 15th 2008, 07:14 PM
Soroban

Hello, Worthey1987!

Could there be a typo in the problem? . . . It's too easy!

Quote:

Simplify: . $\frac{\dfrac{x-y}{x+y} - \dfrac{x+y}{x-y}}{\dfrac{x+y}{x-y} - \dfrac{x-y}{x+y}}$

Factor -1 out of the numerator: . $\frac{\text{-}1\bigg[\dfrac{x+y}{x-y} - \dfrac{x-y}{x+y}\bigg]}{\;\;\;\bigg[\dfrac{x+y}{x-y} - \dfrac{x-y}{x+y}\bigg]}$ . . . and reduce.
November 15th 2008, 07:16 PM
o_O

Just a little colour-coding: $\frac{\ \displaystyle {\color{red}\frac{x-y}{x+y}} - {\color{blue}\frac{x-y}{x+y}} \ }{\ \displaystyle {\color{blue}\frac{x+y}{x-y}} - {\color{red}\frac{x-y}{x+y}} \ }$

Factor out a -1 from the numerator: $= \frac{\ - \left( \displaystyle {\color{blue}\frac{x-y}{x+y}} - {\color{red}\frac{x-y}{x+y}}\right) \ }{\ \displaystyle {\color{blue}\frac{x+y}{x-y}} - {\color{red}\frac{x-y}{x+y}} \ }$

Notice that the thing in parentheses is the same as the same as the bottom. What can you do to them?

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