8x+2<=-14 and 4x-2>10

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- July 19th 2005, 10:09 AMAshiebug3solve and graph
8x+2<=-14 and 4x-2>10

- July 25th 2005, 07:07 PMhtmlmaster
Simple. For the first inequality subtract two from each side, then divide by 8, you get x < -2, for the next one add two to each side, divide by four, and get x > 3. Then draw a number line from -2 to 3, make an open dot at the -2 and three point, draw a line inbetween them.

- June 19th 2007, 05:33 AMJonboy
I'm confused htmlmaster...

We have:

Subtract 2 from both sides:

Divide both sides by 8:

Next we have:

Which goes to:

Thus we get:

How can I have a number greater than 3 and be less than or equal to -2? This seems like a no solution to me. - June 19th 2007, 06:14 AMOReilly

You didn't mention are those inequalites part of system of inequalities or are they independent?

My guess is that htmlmaster solve it believing that they are independent.

If they are system of inequalities then they have no solution since there is no x which satisfies both inequalities. - June 19th 2007, 11:37 AMSoroban
Hello, Ashiebug3!

I wish you would respond and clear up the mystery . . .

Quote:

Graph: . .and .

**separate**problems . . .

The first is: .

Its graph is:Code:`======* - - + - - - - - - - - - -`

-2 0

The second is: .

Its graph is:Code:`- - - - - - - + - - - - o=======`

0 3

Are you*really*having difficulty with the algebra?