# Thread: Trouble With Simple Logarithms :(

1. ## Trouble With Simple Logarithms :(

hey guys

everytime i solve this particular question i end up with x = 1/2

but it's wrong and the answer is actually 3 and i want to know where i went wrong, thanks a lot in advance

2. Originally Posted by jimzer
hey guys

everytime i solve this particular question i end up with x = 1/2

but it's wrong and the answer is actually 3 and i want to know where i went wrong, thanks a lot in advance
Note that:

1. $\displaystyle \log_2 8 = 3$

2. $\displaystyle \log_2 8^{1-x} = (1 - x) \log_2 8$.

By the way, what you've posted isn't an equation ....What's the expression meant to be equal to ...?

3. the book asks to simplify without a calculator, and thanks a lot for that swift reply

4. Originally Posted by jimzer
the book asks to simplify without a calculator, and thanks a lot for that swift reply
Do you see now why the answer is 3 ....?

5. call me silly but no

i see how log(2)8 = 3 cause 2^3 = 8

but there's the x's and i have no clue how to simplify or solve this question :/

6. Originally Posted by jimzer
call me silly but no

i see how log(2)8 = 3 cause 2^3 = 8

but there's the x's and i have no clue how to simplify or solve this question :/
Look at what I posted. Your expression becomes x(3) + (1 - x)(3) = ....

7. .. i cant believe i didnt see that!!

THANKS SO MUCH AGAIN!!