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Math Help - Trouble With Simple Logarithms :(

  1. #1
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    Trouble With Simple Logarithms :(

    hey guys

    everytime i solve this particular question i end up with x = 1/2

    but it's wrong and the answer is actually 3 and i want to know where i went wrong, thanks a lot in advance
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  2. #2
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    Quote Originally Posted by jimzer View Post
    hey guys

    everytime i solve this particular question i end up with x = 1/2

    but it's wrong and the answer is actually 3 and i want to know where i went wrong, thanks a lot in advance
    Note that:

    1. \log_2 8 = 3

    2. \log_2 8^{1-x} = (1 - x) \log_2 8.

    By the way, what you've posted isn't an equation ....What's the expression meant to be equal to ...?
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  3. #3
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    the book asks to simplify without a calculator, and thanks a lot for that swift reply
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  4. #4
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    Quote Originally Posted by jimzer View Post
    the book asks to simplify without a calculator, and thanks a lot for that swift reply
    Do you see now why the answer is 3 ....?
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  5. #5
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    call me silly but no

    i see how log(2)8 = 3 cause 2^3 = 8

    but there's the x's and i have no clue how to simplify or solve this question :/
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  6. #6
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    Quote Originally Posted by jimzer View Post
    call me silly but no

    i see how log(2)8 = 3 cause 2^3 = 8

    but there's the x's and i have no clue how to simplify or solve this question :/
    Look at what I posted. Your expression becomes x(3) + (1 - x)(3) = ....
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  7. #7
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    .. i cant believe i didnt see that!!

    THANKS SO MUCH AGAIN!!
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