Results 1 to 3 of 3

Math Help - Simplifying Indices

  1. #1
    Newbie
    Joined
    Sep 2008
    Posts
    11

    Simplifying Indices

    Hi,

    Could somebody please tell me where I'm going wrong, or if it's the book that's wrong on this (easy) question:

    \frac{2^6}{8^{2\frac{1}{2}}*2^{-\frac{1}{2}}}

    I get:

    \frac{2^6}{(2^3)^{2\frac{1}{2}}*2^{-\frac{1}{2}}}

    = \frac{2^6}{2^{7\frac{1}{2}}*2^{-\frac{1}{2}}}

    = \frac{2^6}{2^7}

    = 2^{-1}

    = \frac{1}{2}



    The book however has the answer as:

    2^\frac{39}{4}


    I'm pretty sure I'm right because multiplying it out gives 0.5, but I tried it in an online solver and they come out with the same answer as the book.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6
    Hello,

    Unless you didn't copy the text well, I don't see any mistake in your working
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member
    Joined
    Nov 2008
    Posts
    461
    Quote Originally Posted by Moo View Post
    Hello,

    Unless you didn't copy the text well, I don't see any mistake in your working
    What about this





    (2^3)^2 = 2^7
    ?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Simplifying an expression involving indices
    Posted in the Algebra Forum
    Replies: 2
    Last Post: February 26th 2011, 05:42 PM
  2. simplifying radicals and fractional indices
    Posted in the Algebra Forum
    Replies: 6
    Last Post: April 16th 2009, 05:33 AM
  3. Replies: 8
    Last Post: February 2nd 2009, 01:28 AM
  4. Indices Help, Please
    Posted in the Algebra Forum
    Replies: 3
    Last Post: January 12th 2009, 06:51 AM
  5. Indices
    Posted in the Algebra Forum
    Replies: 2
    Last Post: January 8th 2009, 06:18 AM

Search Tags


/mathhelpforum @mathhelpforum