# Thread: logarithmic and exponential problems

1. ## logarithmic and exponential problems

I cannot remember how to do this . any help would be appeciated.
logx - log(x+3) = -1

2. Originally Posted by hdrag02
I cannot remember how to do this . any help would be appeciated.
logx - log(x+3) = -1
$\log x- \log(x+3)=-1$

$\log \frac{x}{x+3}=-1$

$10^{-1}=\frac{x}{x+3}$

Can you finish??

$3^{x^2+4x}=27$

$3^{x^2+4x}=3^3$

$x^2+4x=3$

Can you finish?

3. I think i have the right answer, but it seems weird. Heidi

4. Originally Posted by hdrag02
I think i have the right answer, but it seems weird. Heidi
What is it and we'll see how weird it is?

5. ## Hdrag02 problem

is the answer 1/3? for the first problem and -2 + or - the sq root of 7 for the other? I just feel like an idiot. Heidi

6. Originally Posted by hdrag02
is the answer 1/3? for the first problem and -2 + or - the sq root of 7 for the other? I just feel like an idiot. Heidi
Don't know why you feel that way. Your answers are correct!!

7. ## thank you!

Thank You soooooo Much! I really appreciated your help. I will be back! Heidi

8. ## exponential problem# 2

Is there any way you can send me your answer? I was told I had the wrong answer. My Professor had x^2+4x=-3. I am confused. could you explain this to me? Thank you.Heidi