1. 4t+1 = (3-3t)^2

2. 4t+1 = 9-18t+9t^2

3. 9t^2-22t+8 = 0

For this one use the quadratic formula:

So, it would be:

t = (22 + 14) / 18 or t = (22 - 14) / 18

t = 36/18 or t = 8/18

t = 2 or t = 4/9

OR, you could divide the original equation through by 9 to get:

t^2 - (22/9)t + 8/9 = 0

Then factor it as:

(t-2)(t-4/9) = 0

but, these factors might not have been so obvious. When in doubt, use the quadratic formula to find the values