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Thread: What else can I do?

  1. #1
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    Question What else can I do?

    $\displaystyle
    16x^3+16x^2+3x
    $

    $\displaystyle
    x(16x^2+16x+3)
    $

    What else can I do?
    Last edited by Alienis Back; Nov 11th 2008 at 05:56 AM. Reason: there was a mistake, otherwise I would have had to.
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  2. #2
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    $\displaystyle
    16x^3+16x^2+3x
    $

    $\displaystyle
    x(16x^2+16x+3)
    $

    $\displaystyle
    x [(4x)^2+16x+3]
    $

    I have to factor it completely. Anything idea?
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  3. #3
    Super Member
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    Quote Originally Posted by Alienis Back View Post
    $\displaystyle
    16x^3+16x^2+3x
    $

    $\displaystyle
    x(16x^2+16x+3)
    $

    $\displaystyle
    x [(4x)^2+16x+3]
    $

    I have to factor it completely. Anything idea?
    $\displaystyle 16x^2 + 16x + 3 $ this can be factored into


    $\displaystyle ( 4x+ 1) ( 4x +3) $
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  4. #4
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    Dec 2007
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    96
    No, Tweety.
    You must have made a mistake, since it is $\displaystyle 16x^3$, not $\displaystyle 16x^2$. But anyway you helped me to find the right answer. Thanks.


    $\displaystyle
    16x^3+16x^2+3x
    $

    $\displaystyle
    16x^3+12x^2+4x^2+3x
    $

    $\displaystyle
    4x^2(4x+3)+x(4x+3)
    $

    $\displaystyle
    (4x^2+x)(4x+3)
    $
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