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Math Help - Speed/Distance ABC

  1. #1
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    Speed/Distance ABC

    Hey I am doing some exam questions from a mechanics textbook and I am really confused I was just wondering if anyone could help me out The question is:

    A particle moves with uniform acceleration 1/2ms ina horizontal line ABC. The speed of the particle at C is 80ms and the times taken form A to B and from B to C are 40s and 30s.

    What is the speed of the particle at A?

    What is the distance of BC?
    Last edited by andythefox; November 10th 2008 at 10:18 AM.
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  2. #2
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    Quote Originally Posted by andythefox View Post
    Hey I am doing some exam questions from a mechanics textbook and I am really confused I was just wondering if anyone could help me out The question is:

    A particle moves with uniform acceleration 1/2ms ina horizontal line ABC. The speed of the particle at C is 80ms and the times taken form A to B and from B to C are 40s and 30s.

    What is the speed of the particle at A?

    What is the distance of BC?
    Motion from B to C:

    a = 1/2 m/s^2
    t = 30 s
    v = 80 m/s
    x = ?

    Substitute into an appropriate uniform straight line motion formula and solve for x.

    -----------------------------------------------------------------------------

    Motion from A to B:

    a = 1/2 m/s^2
    t = 40 m/s
    v = see below
    u = ?

    Substitute into an appropriate uniform straight line motion formula and solve for u.

    Note that v is the initial velocity in the motion from B to C ...... Therefore:

    Motion from B to C:

    a = 1/2 m/s^2
    t = 30 s
    v = 80 m/s
    u = ? (this is the same as the final velocity v in the motion from A to B).

    Substitute into an appropriate uniform straight line motion formula and solve for u.
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  3. #3
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    thanks alot
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