1. ## Speed/Distance ABC

Hey I am doing some exam questions from a mechanics textbook and I am really confused I was just wondering if anyone could help me out The question is:

A particle moves with uniform acceleration 1/2ms ina horizontal line ABC. The speed of the particle at C is 80ms and the times taken form A to B and from B to C are 40s and 30s.

What is the speed of the particle at A?

What is the distance of BC?

2. Originally Posted by andythefox
Hey I am doing some exam questions from a mechanics textbook and I am really confused I was just wondering if anyone could help me out The question is:

A particle moves with uniform acceleration 1/2ms ina horizontal line ABC. The speed of the particle at C is 80ms and the times taken form A to B and from B to C are 40s and 30s.

What is the speed of the particle at A?

What is the distance of BC?
Motion from B to C:

a = 1/2 m/s^2
t = 30 s
v = 80 m/s
x = ?

Substitute into an appropriate uniform straight line motion formula and solve for x.

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Motion from A to B:

a = 1/2 m/s^2
t = 40 m/s
v = see below
u = ?

Substitute into an appropriate uniform straight line motion formula and solve for u.

Note that v is the initial velocity in the motion from B to C ...... Therefore:

Motion from B to C:

a = 1/2 m/s^2
t = 30 s
v = 80 m/s
u = ? (this is the same as the final velocity v in the motion from A to B).

Substitute into an appropriate uniform straight line motion formula and solve for u.

3. thanks alot