Results 1 to 2 of 2

Math Help - Easy (although hard for me) math problem

  1. #1
    Member
    Joined
    Feb 2008
    Posts
    79

    Easy (although hard for me) math problem

    I have no idea how to do this...

    Suppose that on Wednesday a ipod company earns $17197 from selling ipods @ an even dollar price which is greater than $1 and on Thursday the ipod store earns $17371 from selling ipods @ that same even dollar price as on Wednesday. Determine the number of ipods the company sold each day and @ what even dollar price (greater than $1)?

    ---

    So I'm confused by this "even dollar" thing.

    I thought of just finding the GCD(17197, 17371) which is 29, then dividing each of those numbers by it...

    So 17197/29 = 593 and 17371/29 = 599

    Not sure what this says or what to do now. Thanks for the help.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,658
    Thanks
    598
    Hello, DiscreteW!

    You found the answers . . . you just didn't recognize them.


    On Wednesday a company earned $17197 from selling ipods at an even dollar price
    and on Thursday the company earned $17371 from selling ipods at that same price.
    Determine the number of ipods the company sold each day and at what price?

    - - - - - - - -

    So I'm confused by this "even dollar" thing.
    . .
    I'm sure it means "whole dollar" price.

    I thought of just finding the GCD(17197, 17371) which is 29,
    then dividing each of those numbers by it. . . . . Good!

    So: . 17197 \div 29 \:= \:593\:\text{ and }\;17371 \div 29 \:=\: 599 . . . . Yes!

    Not sure what this says or what to do now.
    Note that 29, 593, and 599 are primes.



    Since 17197 \:=\:29\cdot593, then on Wednesday,

    . . the store sold: . \begin{Bmatrix} 29\text{ ipods at }\$593\text{ each} \\ \text{or} \\ 593\text{ ipods at }\$29\text{ each} \\ \end{Bmatrix}



    Since 17371 \:=\:29\cdot599, then on Thursday,

    . . the store sold: . \begin{Bmatrix}29\text{ ipods at }\$599\text{ each} \\ \text{or} \\ 599\text{  ipods at }\$29\text{ each} \end{Bmatrix}



    Since the price was the same on both days,

    . . \begin{array}{ccc}\text{Wedmesday} & 593\text{ ipods at }\$29\text{ each} \\ \text{Thursday} & 599\text{ ipods at }\$29\text{ each} \end{array}

    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Need Help on a hard problem on discrete math.
    Posted in the Discrete Math Forum
    Replies: 1
    Last Post: July 19th 2011, 03:17 PM
  2. Replies: 5
    Last Post: August 20th 2010, 11:25 AM
  3. help hard math problem
    Posted in the Calculus Forum
    Replies: 2
    Last Post: March 1st 2009, 04:57 AM
  4. Hard but fun math problem
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 15th 2009, 09:31 PM
  5. Hard math problem
    Posted in the Geometry Forum
    Replies: 6
    Last Post: January 12th 2009, 02:43 AM

Search Tags


/mathhelpforum @mathhelpforum